In the given reaction sequence,identify the f | vedclass

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(C) $1$. The starting material is $1,3$-butadiene $(CH_2=CH-CH=CH_2)$.$2$. Addition of $HCl$ at $40^{\circ}C$ (thermodynamic control) to $1,3$-butadie

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$1-$chloro$-3-$iodobutane

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(C) $1$. The starting material is $1,3$-butadiene $(CH_2=CH-CH=CH_2)$.$2$. Addition of $HCl$ at $40^{\circ}C$ (thermodynamic control) to $1,3$-butadiene primarily yields the $1,4$-addition product,which is $1$-chloro$-2-$butene $(CH_3-CH=CH-CH_2Cl)$.$3$. Subsequent addition of $HI$ to $1$-chloro$-2-$butene follows Markovnikov's rule. The proton $(H^+)$ adds to the carbon with more hydrogens,and the iodide $(I^-)$ adds to the more substituted carbon.$4$. The reaction is: $CH_3-CH=CH-CH_2Cl + HI \rightarrow CH_3-CH(I)-CH_2-CH_2Cl$.$5$. The final product $C$ is $1$-chloro$-3-$iodobutane.

In the given reaction sequence,identify the final product $C$:
$CH_2=CH-CH=CH_2$ $\xrightarrow{HCl, 40^{\circ}C} A$ $\xrightarrow{HI} C$
(Note: The reaction proceeds via electrophilic addition to a conjugated diene.)

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In the given reaction sequence,identify the final product $C$:$CH_2=CH-CH=CH_2$ $\xrightarrow{HCl, 40^{\circ}C} A$ $\xrightarrow{HI} C$(Note: The reaction proceeds via electrophilic addition to a conjugated diene.)